A special National Cipher Challenge for extraordinary times › Forums › Bureau of Security and Signals Intelligence Forum › Ciphers and Puzzles from Competitors
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20th April 2020 at 7:10 pm #47735Inactive
TLW Cipher #2
Second to solve it – Bubble-sort has the correct answer.
20th April 2020 at 8:43 pm #47737InactiveTLW CIPHER Hint Posting 4
YWI HMZMWSVW AMWIPC XLIR HMZMHI ERH GSRUYIV IEGL AMXL E XAMWX.
21st April 2020 at 9:36 am #4774710degrees-adminKeymaster@The-letter-wriggler
Base 1? Really??21st April 2020 at 10:05 am #4775210degrees-adminKeymaster@Kford, you’ve make it obvious. N = 121
@TLW, you keep saying “TLW CIPHER Hint Posting X”. But your last hint doesn’t make sense unless it’s really for TLW ABC.
21st April 2020 at 11:50 am #47763Inactive@Madness
All my hint posts: TLW CIPHER, relate to my first posted cipher.
The hint makes perfect sense relating to that.
Could it be possible that you solved it a different way to the way I made it, giving rise to your query?21st April 2020 at 6:42 pm #4778610degrees-adminKeymaster@Madness
For your block affine cipher, HOVERCRAFT AUTOMATIC COMPUTERS MONOTONY21st April 2020 at 9:39 pm #47776InactiveTLW MINI CHALLENGE
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These are all classic ciphers and should give no problem, except maybe #4.
Cipher #4 though has, as far as I am aware, never been used by Harry.
There are cryptic clues within each cipher to help with access to the next.
Keep in practice – enjoy.CIPHER ONE
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LBH UNIR PYHRF NAQ NANTENZF GB URYC LBH TRG FGNEGRQ JVGU RNPU PVCURE.
SBE VAFGNAPR GUR SBYYBJVAT FUBHYQ URYC LBH BCRA HC GUR ARKG PVCURE, AHZORE GJB…
YBIRF GB ERNEENATR GUR ZRFFNTR VA N JNL GUNG ZNXRF VG HAERNQNOYR, OHG GUR PYHR URER JVYY URYC!CIPHER TWO
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WEHLKIE RK RCE WKPHV KA LDMCEPQ – YKT CSUE FTQR VELPYMREV RCE QELKJV LDMCEP. ‘HKUEQ RK PESPPSJBE’ WSQ KOUDKTQHY RCE LHTE, SJ SJSBPSI KA ‘HKUEQ’ BDUDJB RCE WKPV ‘QKHUE’ WCDLC DQ WCSR YKT VDV! WDHH RCEPE OE S LHTE RK RCE AKHHKWDJB LDMCEP WDRCDJ RCE KJE FTQR QKHUEV? PE: HESUDJB RKBERCEP RCDQ LHTE WDHH CEHM YKT QEE RCE JEXR LDMCEP RCSR AKHHKWQ.CIPHER THREE
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ZXN POZSVTX KJSD YWJ ZYEO XHP ARIFRY GIAPRX ZW XVANSRJ, ‘II: GIAGQAM KSBITSME’ CRW OLE NTHK JS ‘MI’ AYL ‘YKRZDRG’ EWTKKLZV AYITXRQ OS RPDRGCMIK, YZC NXV WPVEWG BT PSPV WLG GU WEHI SZ SRKG EO MT. EPR TVBO GHLTYKEKZ MS UCFZ KLVX, SZURZYMIK YZC JOCP CEVP BB WLIPI FZZ, OAK ADXH NCATZRB, MNDQTNK EIH PPZFKMIMENNM LUL ADPL RMG EFYM VEHIEJ.CIPHER FOUR
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MZU HQOQF QGXA KUNH ZK KS OAISM AWMX IH JVMO RQHUUQ MKBL SNQ W NUBLDKFL EXFD EWQUGS, JV FKTUJX VZCTNK VQKE IUWG RZU DG JZAP JWQIP YCC IQWPPHQLG JOODXY HGE ZVEYZHXJ WSWVQ.
Y WVVX SUWH KJKL HNGV FG RZK UQIXAH LXJV QVPFZU KV CX MR MVBXRGWZ OE HA HNMX PUYI VAIZ ZS SKFUNY HS YULGW OG HGFV FG KUP T LITN HOD MHX KJQ VXULU SZ UH WH EYIGLR SUDQN – RFGFN MOI (N4) WJI WUG HGYDO WZCMPSSG MLRO LUTNH. K SKI COS KRHNHP RZU IO QMJQ KP RYJI IFXGZ OUW SIHGLR SZ NMLE HTQ YJHVKFC KP GYYDRZ NZHTN TH, PUWAF AZQ YUVH TMLL CXJZ HC UQIP KOHN, GA ANMX SZVL ZXF!
UR PPF PMVI VX IAGK WZ FSCND SUWH PPF TMLL UXXJQI BXC HGL NFINQFV IKKVI VQQ HMJW AESI MRXY ZMRJ ZH HGL VQSZQ DUQVQIDGJ EUIGESL RCRLXAZP ZI M XFBJDI OZKVA HTQ RVSEH AR KJQ VUYYACHZSJ TJ RZUY SNQD JYOQ, HZF LYKYBXN ‘WXP YWCH HZDP MPSS ACYC EKRHNEJ’ PZURC LQ EFZOKMHNK BA HNQ-AEHMQF-SRFLVXNU.22nd April 2020 at 8:38 am #4779010degrees-adminKeymaster@TLW You’re right, you never know.
22nd April 2020 at 8:38 am #4779110degrees-adminKeymaster… but you were wrong about an inability to use statistics on ciphertext 4.
22nd April 2020 at 8:39 am #4779310degrees-adminKeymaster@Bubble-Sort Yes. Carry on! Several more to do.
22nd April 2020 at 10:43 am #47795Inactive@Madness, thank you for that.
To be honest I do not know how much minimum ciphertext is needed for any one particular type of cipher.
I wonder, is there any info on the internet regarding this?22nd April 2020 at 2:26 pm #4780610degrees-adminKeymaster@TLW It’s called “unicity distance” or something like that. As for your challenge, I just modified my program to use word spacing and it was able to get 80% or more of the plaintext.
22nd April 2020 at 9:52 pm #4781910degrees-adminKeymasterHere’s a good cipher:
2110100200202220121021010102222201
0220222202120121001022212110202021
00100122221002202222001120110010
11012222022011110021010112[linebreaks don’t mean anything, I just wrapped it for you, Harry]
23rd April 2020 at 9:23 am #4783110degrees-adminKeymasterNote: Please submit answers in the form ‘KA-1 ABC XYZ’, where ABC and XYZ are three random letters from two of the seven words in the plaintext that have three or more letters (it doesn’t matter which order the words or the letters are in). (e.g.: If the two of the words were ‘Cipher’ and ‘Puzzle’, you could put ‘KA-1 CIP ZLE’ or ‘KA-1 PUZ HER’)
23rd April 2020 at 4:58 pm #47788InactiveTLW Mini challenge: Very minor issue.
In cipher #3 the seventh word should have been t…. not s….. but hey, I made all the script and clues up and put all this together in just over two and a half hours before posting, it’s easy to over look something like that!
Thought I’d say before someone else points it out. -
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